Shaoyun Wang
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Mechanics · 2021-06-06

Contiunuous condition

Displacement

Obviously, according to the continuous condition, the displacements u⃗\vec{u} is continuous at the surface SS. If it is not, there are holes or overlaps in the body which is contradictory to the continuous condition.

Assume the interface SS is z=0z=0.

Solarized darkSolarized Ocean

Derivatives of displacements

The derivatives of the displacements along the tangent direction on the surface is continuous too. The definition of two derivatives on both surface are

ui,j1=∂ui1∂xj=lim⁡Δxi→0u1(xi+Δxi)−u1(xi)Δxiui,j2=∂ui2∂xj=lim⁡Δxi→0u2(xi+Δxi)−u2(xi)Δxi,i=1,2,3;j=1,2u_{i,j}^1=\frac{\partial u_i^1}{\partial x_j}=\lim_{\Delta x_i \rightarrow 0} \frac{u^1(x_i + \Delta x_i) - u^1(x_i)}{\Delta x_i} \\ u_{i,j}^2=\frac{\partial u_i^2}{\partial x_j}=\lim_{\Delta x_i \rightarrow 0} \frac{u^2(x_i + \Delta x_i) - u^2(x_i)}{\Delta x_i}, i=1,2,3;j=1,2

And because of the continuous condition of u⃗\vec u, we have

u1(xi+Δxi)=u2(xi+Δxi)u1(xi)=u2(xi).u^1(x_i + \Delta x_i)=u^2(x_i + \Delta x_i)\\ u^1(x_i) = u^2(x_i).

Therefore, we have

ui,j1=ui,j2u_{i,j}^1=u_{i,j}^2

Stress

According to the static condition (without inerial force),

σij1nj−σij2nj=σij,j1−σij,j2=ρ1u¨i−ρ2u¨i=0\sigma_{ij}^1 n_j - \sigma_{ij}^2 n_j = \sigma_{ij,j}^1 - \sigma_{ij,j}^2 = \rho_1 \ddot{u}_i-\rho_2 \ddot u_i=0

Therefore, σ33,σ13,σ23\sigma_{33}, \sigma_{13}, \sigma_{23} are continuous.

Strain

According to the constitutive law

ε11=1E(σ11−ν(σ22+σ33))ε22=1E(σ22−ν(σ11+σ33))ε33=1E(σ33−ν(σ11+σ22))ε12=12Gσ12ε13=12Gσ13ε23=12Gσ23\begin{aligned} \varepsilon_{11} &=\frac{1}{E}\left(\sigma_{11}-\nu\left(\sigma_{22}+\sigma_{33}\right)\right) \\ \varepsilon_{22} &=\frac{1}{E}\left(\sigma_{22}-\nu\left(\sigma_{11}+\sigma_{33}\right)\right) \\ \varepsilon_{33} &=\frac{1}{E}\left(\sigma_{33}-\nu\left(\sigma_{11}+\sigma_{22}\right)\right) \\ \varepsilon_{12} &=\frac{1}{2 G} \sigma_{12}\\ \varepsilon_{13} &=\frac{1}{2 G} \sigma_{13}\\ \varepsilon_{23} &=\frac{1}{2 G} \sigma_{23} \end{aligned}

And definition of strain

ε11=∂u1∂x1ε22=∂u2∂x2ε33=∂u3∂x3ε12=12(∂u1∂x2+∂u2∂x1)ε13=12(∂u1∂x3+∂u3∂x1)ε23=12(∂u2∂x3+∂u3∂x2)\begin{aligned} \varepsilon_{1 1} &= \frac{\partial u_{1}}{\partial x_{1}} \\ \varepsilon_{2 2} &= \frac{\partial u_{2}}{\partial x_{2}} \\ \varepsilon_{3 3} &= \frac{\partial u_{3}}{\partial x_{3}} \\ \varepsilon_{1 2} &= \frac{1}{2}\left(\frac{\partial u_{1}}{\partial x_{2}}+\frac{\partial u_{2}}{\partial x_{1}}\right) \\ \varepsilon_{1 3} &= \frac{1}{2}\left(\frac{\partial u_{1}}{\partial x_{3}}+\frac{\partial u_{3}}{\partial x_{1}}\right) \\ \varepsilon_{2 3} &= \frac{1}{2}\left(\frac{\partial u_{2}}{\partial x_{3}}+\frac{\partial u_{3}}{\partial x_{2}}\right) \end{aligned}

Therefore, ε11,ε22,ε12\varepsilon_{11}, \varepsilon_{22}, \varepsilon_{1 2} are continuous.

Conclusion

ContiunuousUncontiunousUndetermined
Displacementsu1,u2,u3u_1,u_2,u_3//
Stressσ33,σ13,σ23\sigma_{33}, \sigma_{13}, \sigma_{23}σ12\sigma_{12}σ22,σ33\sigma_{22},\sigma_{33}
Strainε11,ε22,ε12\varepsilon_{11}, \varepsilon_{22}, \varepsilon_{1 2}ε13,ε23\varepsilon_{13}, \varepsilon_{23}ε33 \varepsilon_{33}